Total acidity and sodium hydroxide concentrations

Made an interesting mistake this last weekend...

I used the sringe and technique from one kit - 15cc wine, start with

10cc NaOH - what you used to tirate to 8.2 is the TA with NaOH from another kit and got unusually high TAs.

Turns out technique 1 used NaOH with 0.2 normality and the other used

0.1.

Is there a formula for TA that includes a variable for the Normality of NaOH so I recalc what my starting acids were?

thx, dan

Use this formula... %(W/V) = 7.5x(VbxN)/VwxF) Vb = ml of naoh used Vw= ml of wine used N= normality of NaOH F= normality factor if NaOH is not .1N >

TA = 75 * N * Vn / Vs

where TA = titratable acidity (as tartaric acid (g/l)) N = Normality of NaOH (0.2 in your case) Vn = Volume of NaOH (ml) Vs = Volume of sample (ml)

Ben

Thanks Greg.

What is F, the normality factor? If I used .2N would this be 2? dan

It would be .2

2 would be almost a 10 % solution

BTW the formula is in Margalits handbook for small wineries page 160 . Great book that covers making wine in small wineries .