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Need to make 0.0667N NAOH solution

I am trying to make a 0.0667N NAOH solution for titration to find TA. I have .2N NAOH solution for going the phenolpthalein route but don't like using that technique because of inaccuracy. I want to use pH meter to find end point. I know the grams/liter of NAOH needed to make the solution but would have to buy the NAOH from chem supply. One supplier wanted $23.50 for 200 grams of lab quality NAOH and on top of that wanted $37.50 to ship it! Forget that! All I want to know is how many milliliters of distilled/deionized water I need to add to the .2N NAOH solution to make it a 0.0667N NAOH solution. Anyone?

Reply to
jestar
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The volume of water you need to add depends on the volume of solution you have to start with, or, alternatively, the volume of solution you want to end up with.

Easiest to do it as a simple ratio calculation. The solution you have now is (0.2 / 0.0667) = 3 times as strong as you need, so you need to dilute it to one-third of its present strength -- which means that you add *two* parts water to one part solution.

Reply to
Doug Miller

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